Jason (jcreed) wrote,
Jason
jcreed

-

Wheelbarrow idea: Instead of the 'barrow being
one monolithic pile, lay the cards out in a row
in the center of the table, face down. Leader can
then, under circumstance X for some X, look at
a card, and choose to play it or play out of
eir hand. I was thinking originally X would
be the null circumstance, but I think that might
lead to too much information gained too quickly.
Though maybe not.
In any event, I think it ought to be the case
that when one player is out of cards, cards left
in the other player's hand and barrow should be
worth 1/2 trick each, so that the number of tricks
is constant.
2 players: 3579JQKA of all four suits, lo joker, hi joker.
13-card hands, 8 in barrow.
3 players: (totally untested, just thinking) 3-A
2C is lo joker, 2S is hi joker, and 2D depends
on whether the bid is full; if it isn't, 2D is
the loser -- if it is, then 2D takes the place
of the loser in the trump suit.
13-card hands, 12 in barrow.
Scoring, on a win: declarer: 1 pt for each trick bid,
1 pt for each trick won. 17 points for the player
holding the loser, if different from the declarer.
on a loss: declarer: -3 pts for each trick bid.
Each of the following may occur only
-once- per hand:
* A suit partial
* A rank partial
* An empty bid
* Any specific full bid
Ranking of bids is by suit first (SHDC) then rank.
No-suit and no-rank are respectively higher than all
suits and all ranks.
(Okay, maybe: Leader can always lead from the barrow,
and a leader who also won the trick before last can lift
a card)
If a player is out of cards, e picks a card from the
barrow and plays it face down. (It loses, even to
the loser)
The loser is its own suit. If it is led, the suit of the
next real card becomes the current suit, however; the third
player (if any*) must follow -this- suit if possible, and the
high card of -this- suit (or the high card of trump)
wins.
*The third player may very well -be- the player
of the next valid card. e.g.:
Player A leads the loser. Player B is out of cards,
and so drops from the barrow. Player C plays some random
card, and automatically wins the trick.

Damn.
This is confusing. May have trouble
convincing someone besides pos to play
the 3-player version.
Hell, may have trouble convincing even pos
the bid-uniqueness rules are worthwhile.
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